(1/6x^2)+(1/2x)=1/3x^2

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Solution for (1/6x^2)+(1/2x)=1/3x^2 equation: 



(1/6x^2)+(1/2x)=1/3x^2

We move all terms to the left:

(1/6x^2)+(1/2x)-(1/3x^2)=0



Domain of the equation: 6x^2)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3x^2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(1/6x^2)+(+1/2x)-(1/3x^2)=0

We get rid of parentheses

1/6x^2+1/2x-1/3x^2=0

We calculate fractions

We do not support expression: x^5

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